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GT350 Brakes with 18" Wheels

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1,249
1,243
In the V6L
Well, you're definitely making the item in question obscure. It looks like there might be a rotor hat in there somewhere, but it's not clearly visible.

In any case, the math is simple. 4,000 pound car slowing at 1g means a force of 4,000 pounds-force pushing back on it. F/R weight distro is around 55/45 static, so lets say a 10 point shift for weight transfer under braking, that puts it at 65/35. 65% of 4,000 pounds is 2,600 pounds, and it's split evenly between the two front tires at 1,300 pounds-force each. The "r" of the tire is around 13 inches, so if we just call it 1 foot, we've got a caliper and pads delivering 1,300 ft-lbs of torque to each of the two front brake rotors and hats. And 1,000 degrees F has a rotor glowing but not very brightly; it's not an exceptionally high brake rotor temp for a 4,000 pound car slowing at the end of a straight. Hence my question.
 
Well, you're definitely making the item in question obscure. It looks like there might be a rotor hat in there somewhere, but it's not clearly visible.

In any case, the math is simple. 4,000 pound car slowing at 1g means a force of 4,000 pounds-force pushing back on it. F/R weight distro is around 55/45 static, so lets say a 10 point shift for weight transfer under braking, that puts it at 65/35. 65% of 4,000 pounds is 2,600 pounds, and it's split evenly between the two front tires at 1,300 pounds-force each. The "r" of the tire is around 13 inches, so if we just call it 1 foot, we've got a caliper and pads delivering 1,300 ft-lbs of torque to each of the two front brake rotors and hats. And 1,000 degrees F has a rotor glowing but not very brightly; it's not an exceptionally high brake rotor temp for a 4,000 pound car slowing at the end of a straight. Hence my question.

Well, you're definitely making the item in question obscure. It looks like there might be a rotor hat in there somewhere, but it's not clearly visible.

In any case, the math is simple. 4,000 pound car slowing at 1g means a force of 4,000 pounds-force pushing back on it. F/R weight distro is around 55/45 static, so lets say a 10 point shift for weight transfer under braking, that puts it at 65/35. 65% of 4,000 pounds is 2,600 pounds, and it's split evenly between the two front tires at 1,300 pounds-force each. The "r" of the tire is around 13 inches, so if we just call it 1 foot, we've got a caliper and pads delivering 1,300 ft-lbs of torque to each of the two front brake rotors and hats. And 1,000 degrees F has a rotor glowing but not very brightly; it's not an exceptionally high brake rotor temp for a 4,000 pound car slowing at the end of a straight. Hence my question.
3D Printing = Rapid Protoyping
Offsets matter because we only design things that use easily obtainable service parts, making a hat is much easier than modifying brake rotors.
 
1,249
1,243
In the V6L
3D Printing = Rapid Protoyping
Offsets matter because we only design things that use easily obtainable service parts, making a hat is much easier than modifying brake rotors.
So, from that reply, can I infer that you're using 3D printing to check for fit, but not as a production process?
 

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